Odpowiedzi

2010-03-14T19:14:33+01:00
V = 54 km/h = 15m/s
t = 1 minuta = 60 sek

a=v/t
a=15/60=1/4 m/s^2

s=(at^2)/2=(1/4*3600)/2=900/2= 450m

Droga wynosi 450 m, a opóźnienie 1/4 m/s^2
2010-03-14T19:18:21+01:00
Vk=Vo-at
a=(Vo-Vk)/t
a=(15m/s-0m/s)/60s
a=15m/s/60s
a=1/4m/s²

S=Vot-1/2at²
S=15m/s*60s-1/2*1/4m/s²*(60s)²
S=900m-1/8m/s²*3600s²
S=900m-450m
S=450m

54km/h=15m/s
1 min = 60 s