Odpowiedzi

2010-03-16T10:06:18+01:00
8x+36x²-10-45x>36x²-12x+1
-33x-11>0
3x<-1
x<-⅓
1 5 1
  • Użytkownik Zadane
2010-03-16T10:06:28+01:00
4x^3 - 4x^2 - 5x^2 + 5x + x - 1 = 0
-9x^2 and 6x
4x^2(x-1) - 5x(x-1) + (x-1) = 0
= (x-1)(4x^2 - 5x + 1) = 0
= (x-1)(4x-1)(x-1) = 0