Odpowiedzi

2009-10-26T08:19:15+01:00
W(x)=x⁶-3x⁴+3x²-1=(x³-1)(x³+1)-3x²(x²-1)=
=(x-1)(x²+x+1)(x+1)(x²-x+1)-3x²(x-1)(x+1)=
= (x-1)(x+1)[(x²+x+1)(x²-x+1)-3x²]=
=(x-1)(x+1)[x⁴-x³+x²+x³-x²+x+x²-x+1-3x²]=
=(x-1)(x+1)(x⁴-2x²+1)=
=(x-1)(x+1)(x²-1)²=
=(x-1)(x+1)[(x-1)(x+1)]²=
=(x-1)³(x+1)³

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