Odpowiedzi

2009-10-26T08:33:43+01:00
40x-120-x²+1+x-1=5x-5-(x²+9)-2
41x-x²-120+1-1=5x-5-x²-9-2
41x-x²+x²-5x=120-9-2-5
36x=104
x=9;26
2009-10-26T08:40:17+01:00
40(x-3)-(x+1)(x-1)=5(x-1)-(x+3)²-2
40x-120-x²+1=5x-5-(x²+6x+9)-2
40x-x²-120+1=5x-5-x²-6x-9-2
40x-x²+x²-5x+6x=120-1-9-2-5
41x=103
x=103/41