Odpowiedzi

Najlepsza Odpowiedź!
2010-03-16T21:16:09+01:00
M² - 3mn +2n² - m = 0
[m -(3/2)n]² -(n/2)² - m = 0
[m - (3/2)n -n/2]*[m -(3/2)n +n/2] = m
[m - (4/2)n]*[m - n] = m
[ m -2n]*[ m - n] = m
czyli
[m -2n]*[m -n] = 1*m
(m -2n = 1 ∧ m -n = m ) lub (m -2n) = m ∧ (m-n) = 1 )
(m - 2n = 1 ∧ n = 0 ) lub ( - 2n = 0 ∧ m = 1 + n )
( m = 1 ∧ n = 0 ) lub ( n = 0 ∧ m = 1 )
Odp. m = 1 oraz n = 0.