Odpowiedzi

2010-03-17T12:18:57+01:00
A) (2x-3)-(x+5)+(x+4) = 2x-3-x-5+x+4=2x-4
b) (3a-20)-(a+4)+(a-3) = 3a-20-a-4+a-3 = 3a-27
2010-03-17T12:19:26+01:00
A) (2x-3)-(x+5)+(x+4) =2x-3-x-5+x+4=2x-4
b) (3a-20)-(a+4)+(a-3) =3a-20-a-4+a-3=3a-27
2010-03-17T12:22:06+01:00
A) 2x-3-x-5+x+4
2x-x+x=3-4+5
2x=4/:2
x=2
b)3a-20-a-4+a-3
3a-a+a=20+4+3
3a=27/:3
a=9