Odpowiedzi

2009-10-26T21:18:52+01:00
Dane: V = 18 km/h = 5 m/s Vk = 0 m/s t = 4 s
Szukane: a = ? S = ?
Vk = V - at
a = (V - Vk)/t a = (5 - 0)/4 a = 1,25 m/s^2
S = at^2/2 S = 1,25*4^2/2 S = 1,25*16/2 S = 20/2 S = 10 m
A więc opóźnienie wynosi 1,25 m/s^2, a droga hamowania to 10 m.
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