Odpowiedzi

2010-03-18T13:15:04+01:00
CuO= 64u + 16 u= 80 u
st atomów 1/1
st mas pierw 64/16= 4/1
NH3= 14u + 3*1u= 14+ 3= 17u
st atomów= 1/3
st mas pierw= 14/3
N2O5= 2*14u + 5* 16 u= 28u + 80u= 108u
st ato= 2/5
st mas= 28/80=14/40=/7/20
FeO= 56u + 16u= 72u
st atom= 1/1
st mas= 56/16