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2010-03-18T17:16:29+01:00
(4a³b²+2c)(1-3a+4b-8c)=
=(4×(1/2)³×-2+2×1/4)(1-3×-1/2+4×(-2)-8×1/4)=
=(-1/2×(-2)+1/2)(1-3/2-8-2)
=(1 1/2×(-10 1/2)=
=-10 1/4