Odpowiedzi

2010-03-18T19:53:37+01:00
2t-(3t+1)=6
2t-3t-1=6
-t-1=6/(-1)
t=-1/6

-(4+x)=2(3-x)
-4-x=6-2x
-4+2=x-2x
-2=-x/(-2)
1=x


3(y+6)-y=2(y+9)
3y+18-y=2y+18
3y-y-2y=-18+18
y=-1

(x-7)-2(3x+5)=3
x-7-6x-10=3
x-6x=7+10+3
-5x=20/(-5)
x=-4