Odpowiedzi

2010-03-18T20:13:56+01:00
MSnO2 = 119u + 32u = 151u

151u - 100%
119u - x
x= 119*100/:151
78,8 % Sn
O = 100-78,8 = 21,2 %

mK3PO4 = 117u+31u+64u = 212 u
212u - 100%
117 - x
x= 117*100 /:212
x= 55,1 % K

212u - 100 %
31u - x
x= 31*100/:212
x=14,62 % P

212u - 100%
64u - x
x= 64*100/:212
x= 30,18 % O

proszę ;)
2010-03-18T20:19:50+01:00
SnO2=118+2*16=150u Sn%=118/150*100%=78,66
O%=32/150*100%=21,34

K3PO4=3*39+30+4*16=117+30+64=211 K%=117/211*100%=55,45
P%=30/211*100%=14,21
O%=64/211*100%=30,34