Odpowiedzi

2010-03-18T23:40:03+01:00
1a
P=4pir^2
P=4pi32
P=128
V=4/3pir^3
V= 4/3pi 64*2√2
V=512/3pi√2
1b
srednica 16√3
r = (16√3)/2
r= 8√3
P=4pi (8√3)^2
P=768

V=4/3pi r^3
V=4/3pi(8√3)^3
V=2048pi

2.
v=1/3pi r^2 *h
v= 1/3pi 16*8
v=128/3 pi
1 5 1
2010-03-18T23:43:17+01:00
A) Pc = 4πr² = 4π(4√2)² = 128π
v = 4/3πr³ <--oblicz sobie z tego wzoru

b)Pc = 4πr² = 4π192 = 768π


v = 1/3 Pp * H = 1/3π16*8=128/3π
1 5 1