Odpowiedzi

2010-03-19T16:12:38+01:00
A) Mcz = 32u + 2 * 16u = 64u
64u - 100%
32u - 50% -> siarka
2 * 16u - 50% -> tlen
b) wzór sumaryczny: Al₂S₃
Mcz = 2 * 27u + 3 * 32u = 54u + 96u = 150u
150u - 100%
96u - x
150x = 9600 |: 150
x = 64% -> siarka
100% - 64% = 36% -> glin
3 3 3
2010-03-19T16:12:41+01:00
A)SO3
M SO3= 80 g
S= 32g/80g*100% = 40%
O= 48g/80g*100% = 60%
b) Al2S3
M Al2S3 = 150g
Al= 54g/150g*100%=36%
S= 96g/150g*100%=64%
38 4 38
2010-03-19T16:14:02+01:00
A) SO2
M.at.= 64u

%S= 32/64 x 100% = 50%
%O2= 100% - 50% = 50%

b)Al2S3
M.at.= 100u

%Al2= 54/150 x 100% = 36%
%S3= 100% - 36% = 64%

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