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  • Użytkownik Zadane
2010-03-20T21:50:28+01:00


2KClO_3 => 2KCl + 3O_2

1dm^3 O_2---------------1,43g
6,72 dm^3 O_2------------x[g]
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1 dm^3 * x = 6,72 dm^3*1,43g


x= 6,72 dm*1,43g//1dm3=9,6096g≈9,61


m KClO_3 - m O_2 = m KCl

24,5g - 9,61g = 14,89 g
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