Odpowiedzi

2010-03-21T12:21:05+01:00
A = 2
H = 2

Pp = ¼ * a² * √3
Pp = ¼ * 4 * √3
Pp = √3 [j²]

Pb = 3 * a * H
Pb = 3 * 2 * 2
Pb = 12 [j²]

Pc = 2Pp + Pb
Pc = (2√3 + 12) [j²]

odp. szukane pole to 2√3 + 12.
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