Odpowiedzi

2010-03-22T21:46:09+01:00
(2x-3)-(x+5)+(x+4)= 2x-3-x-5+x+4=2x-4

4(2y-7y²)-3(y²-3y)=8y-28y²-3y²+9y=-31y²+17y

(3a-2)-(a+4)+(a-3)=3a-2-a-4+a-3=3a-9

-5(2b+3z)+(2b-4z)= -10b-15z+2b-4z=-8b-19z
1 5 1
2010-03-22T21:47:49+01:00
(2x-3)-(x+5)+(x+4)= 2x-3-x-5+x+4= 2x-4

4(2y-7y²)-3(y²-3y)=8y-28y²-3y²+9y= -31y²+17y

(3a-2)-(a+4)+(a-3)= 3a-2-a-4+a-3 = 3a-9

-5(2b+3z)+(2b-4z)= -10b-15z+2b-4z = -8b-19z
1 5 1