Odpowiedzi

2010-03-23T17:19:53+01:00
Q= 200 C
t = 2s
W = 4000 J
U = ?
U = W/q
U = 4000 J/200 C
U = 20 V ; [ J/C] = [ V*A*s/A*s] = [ V]
I = ?
I = q/t
I = 200 C/2s
I = 100 A
R = ?
R = U/I
R = 20 V/100 A = 0,2 oma
moc P = ?
P = U*I
P = 20 V * 100 A = 2000 W = 2 kW
praca jest dana w zadaniu