Odpowiedzi

2010-03-23T16:55:48+01:00
Zad 1
3*(1/2)2 + -2*-1/2 - (-2) = 3 * 1/4 + 1 +2 = 3/4+3 = 3i 3/4
3(-2-1)-(2*-2 +1)+(2*1-1)+2= (3*-3) +4-1+2-1+2=-9+4-1+2-1+2= -3

zad 2
(2a-3b)+(-2a+4b) = 2a-3b-2a+4b=b
(x-2)-(4x+2y-1) = x-2-4x-2y+1= -3x-2y-1
-3(x+4y-2) = -3x-12y+6
4a2( 3a3-a) = 12a5-4a3
2(x-y)-3(x+1)+(y-4) = 2x-2y-3x-3+y-4= -x-y-7
-b(a-b)+(a+b)3a= -ab+b2 + 3a2+3ab= 2ab +3a2 + b2

zad 4
12a-4b = 4(3a-b)
3xy-6x+9x2 = 3x(y-2+3x)
(a-b)3a-b(a-b) = (a-b)2 (3a-b)

zad 5
x+x+x+x=4x