Odpowiedzi

2009-10-28T18:38:20+01:00
L = 2πr

a.1
2 × π × 1 = 2π

b.2
2 × π × 2 = 4π

c.3
2 × π × 3 = 6π

d.4
2 × π × 4 = 8π

średnicy :

a.6
r=3
2 × π × 3 = 6π

b.9
r=4,5
2 × π × 4,5 = 9π

c.12
r=6
2 × π × 6 = 12π

d.18
r=9
2 × π × 9 = 18π

Pozdrawiam :)
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2009-10-28T18:41:01+01:00
WZORY:
l = 2π * r
l = π * d

promieniu :
a.1
l = 2π
b.2
l = 4π
c.3
l = 6π
d.4
l = 8π

i średnicy :
a.6
l = 6π
b.9
l = 9π
c.12
l =12π
d.18
l=18π
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