Odpowiedzi

2010-03-23T22:22:01+01:00
Dane:
t = 20min = 20 × 60s = 1200s
F = 20kN = 20 000 N
s = 2km = 2 000m

Szukane:
P = ?
W = ?

Wzory:
P = W/t W = F × s

W = 20 000N × 2 000 m
W = 40 000 000 J = 40MJ

P = 40 000 000 J : 1200s
P ≈ 33 333 W ≈ 33,3 kW

Odp.: Moc silnika wynosi ok. 33,3 kW .
2010-03-23T22:25:16+01:00
T= 20 min = 1200 s
F= 20 kN = 20 000 N
s= 2 km = 2000 m

P=W/t=F*s / t
P= 20000*2000 /1200= 400 000 / 12 = 100 000 / 3 = 33 333,(3) W
=33kW
2010-03-23T22:25:34+01:00
Witaj
dane t=20min=1200s, F=20 kN, s=2km=2000m
szukane P

P = W/t.........W = F *s
P = F *s/t = 20 kN *2000m/1200s = 33,33 kW

Moc silnika wynosi 33,33 kW

Semper in altum.........................pozdrawiam