Odpowiedzi

2010-03-24T14:24:46+01:00
3β-4α=α+β
2β= 5α
β= 5/2α
2(3α+β)+(3β-4α)+α+β =360
6α+2β+3β-4α+α+β =360
3α+6β =360 /:3
α+2β =120
α+5α =120
6α =120
α=20

β=5/2 *20= 50


22 4 22