Odpowiedzi

2010-03-24T22:09:16+01:00
A]
v=πr²h+⅓πr²h=
π×4²×5+⅓π×4²×3=
80π+16π=96πj.³

pole=πr²+2πrh+πrl=π×4²+2π×4×5+π×4×5=16π+40π+20π=76πj.²
b]
l=5√2

v=πr²h+2×⅓²h=π×5²×6+⅔π×5³=150π+250/3π=233⅓πj.³

pole=2πrh+2πrl=2π×5×6+2π×5×5√2=60π+50√2π=10π(6+5√2)j.²
c]
h=√10²-8²=√36=6
h=13

v=πr²h=π×8²×13=832πj.³
pole=2πrh+2πrl=2π×8×13+2π×8×10=208π+160π=368π