Odpowiedzi

2010-03-24T22:46:40+01:00
(x+1)^3-(2x-3)^2-(x+3)^2+2(x-2)(x+2)=11x-23-3x(do potegi 2)
2010-03-24T22:47:22+01:00
(x+1)^3-(2x-3)^2-(x+3)^2+2(x-2)(x+2)=
(x+1)(x^2+2x+1) -(4x^2-12x+9)-(x^2+6x+9)+x^2-4=
x^3+ 2x^2+x+x^2+2x+1-4x^2+12x-9-x^2-6x-9+x^2-4=
x^3-x^2+9x-21
2010-03-24T22:52:51+01:00
(x^+2x+2)3-(4x^-12x+9)2-(x^+6x+9)2+2(x^-4)=x^+6x+6-(8x^-24+18)-(2x^+12x+18)+2x^-8=x^+6x+6-8x^+24-18-2x^-12-18+2x^-8=-7x^+6x-16