Odpowiedzi

2010-07-12T14:31:51+02:00
A)
N = (50 nad 5) = [ 50 !]/[ 5! *45 !] = [46*47*48*49*50]/[2*3*4*5] =
= 20*46*47*49
n(A) = (15 nad 2)*(35 nad 3) = [15!/(2! * 13!]*[35!/(3! * 32!)] =
= 7*11*15*17*35
P(A) = n(A) / N = [7*11*15*17*35] / [20*46*47*49] =
= [11*15*17]/ [4*46*47] = 2805/8648 ≈ 0,336
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  • Użytkownik Zadane
2010-07-12T14:42:31+02:00
A)
N = (50po5) = ( 50 !)/( 5! *45 !) = [46*47*48*49*50]/(1*2*3*4*5) =
= 3178140

n(A) = (15 po 2)*(35 po3) = (15!/(2! * 13!]*[35!/(3! * 32!)) =
= (14*15/1*2)*(33*34*35/1*2*3)=105+6545=6650

P(A) =6650/3178140=665/317814
3 2 3
2010-07-12T15:23:51+02:00
N = (50 nad 5) =[ 50 !]/[ 5! *45 !]= [46*47*48*49*50]/[2*3*4*5] = 20*46*47*49

n(A) = (15 nad 2)*(35 nad 3) = [15!/(2! * 13!]*[35!/(3! * 32!)] = 7*11*15*17*35

P(A) = n(A) / N = [7*11*15*17*35] / [20*46*47*49] = [11*15*17]/ [4*46*47] = 2805/8648 ≈ 0,336
2 2 2