Odpowiedzi

2010-03-26T21:29:23+01:00
Zadanie1
tgα = sinα/cosα
sinα/cosα = 3/4
4sin = 3 cos /4
sin = 3/4cos
sin² + cos² = 1
(3/4cos)² + cos² = 1
9/16cos² + cos² = 1
25/16cos² - 1 = 0 : 25/16
cos² - 25/16 = 0
(cos-5/4)(cos+5/4) = 0
cos = 5/4 ∨ cos = -5/4 = nie spelnia warunku zadania
sin = 3/4 × 5/4 = 15/16
sin + cos = 15/16 + 5/4 = 35/16