Odpowiedzi

2010-03-26T13:09:51+01:00
Pc = 4πR²

1/3*4πR² = 48π |:1/3
4πR² = 144π |:4π
R² = 36
R = √36
R = 6

V = 4/3πR³

V = 4/3*π*6*6*6
V = 4/3π*216
V = 288π [cm³]
3 5 3
2010-03-26T13:11:50+01:00
V=4/3πr³
P=4πr²

1/3*4πr²=48π
4/3πr²=48π
r²=48π*3/4/π
r²=144/4
r²=36
r=6 cm

V=4/3π*6³
V=4/3π*216
V=288π cm³
1 5 1
2010-03-26T13:15:51+01:00
1/3P=48πcm² /*3
P=144πcm²
P=4πr²
4πr²=144πcm² /:π
4r²=144cm² /:4
r²=36cm²
r=√36cm²
r=6cm
V=4/3πr³
V=4/3π6cm³
V=4/3π216cm³
V=288cm³
odp: Objętość kuli wynosi 288cm³
2 3 2