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2009-10-29T20:04:31+01:00
(2x+1)÷x=3x D:x∈R/{0}
(2x+1-3x²)÷x=0
(-3x²+2x+1)÷x=0
Δ=4+12=16
√Δ=4
x₁=(-2+4)÷-6=-1/3
x₂=(-2-4)÷-6=1
2009-10-29T20:06:22+01:00
2x+1/x=3x /×

2x+1=3x²
-3x²+2x+1+0
Δ=b2-4ac
Δ=4+12=16
√Δ=4

x1=-b+√Δ/2a
x1=-2+4/-6=-1/3

x2=-b-√Δ/2a
x2=-2-4/-6=1