Odpowiedzi

2010-03-27T21:24:58+01:00
R=5 dm
H=9cm=0,9dm

v=pi*r^2*H
v=pi*25*0,9
v=22,5pi [dm^3]

Pc=2pi*r*(r+h)
PC=pa10*(5+0,8)
Pc=58 pi dm^2
2010-03-27T21:25:40+01:00
5dm=50cm


V=πr²*h
V=π*50²*9
V=2500π*9
V=22500π[cm³]

P=2πr²+2πr*h
P=2π*50²+2π*50*9
P=5000π+900π
P=5900π[cm²]
2010-03-27T21:26:05+01:00
Pole i objętość walca r=5dm. , H=9cm.
r=5dm=50cm
V=πr²H
V=50² * 9π
V=22500πcm³ ≈ 70650 cm³

Pp = 2πr²+2πrH
Pp= 2πr (r+H)
Pp=2π*50* (50+9) = 100π * 59= 5900πcm² ≈ 18526cm²