Odpowiedzi

2010-03-28T20:41:43+02:00
A) n= 1/7k
b) k= a-6
c) y= -z+7
d) c= d/b -a
e) k= 1/2x-1
f) n=2/7k-5
2010-03-28T20:45:37+02:00
A)k=7n; n
k=7n/:7
k/7=n

b)a=k+6; k
a=k+6/-6
a-6=k

c)z=7-y; y
z=7-y/-7
z-7=-y/*(-1)
-z+7=y

d)d=a+bc; c
d=a+bc/-a
d-a=bc/:b
(d-a)/b=c

e)x=2k+1; k
x=2k+1/-1
x-1=2k/:2
(x-1)/2=k

f)2k=7n+5; n
2k=7n+5/-5
2k-5=7n/:7
(2k-5)/7=n