Odpowiedzi

2010-03-29T19:36:22+02:00
MCaCO3 =40+12+48=100
n=12 moli
n=m/M
m=n*M=12*100=1200g
2010-03-29T19:37:46+02:00
CaCO₃ -> 40+12+3*16=100g
1mol=100g
12moli -> 12*100=1200g
2010-03-29T19:40:08+02:00
1 mol CaCo3 to 40g + 12g + 48g = 100g zatem 12 moli to 12*100g= 1200g