Odpowiedzi

2010-03-30T14:19:36+02:00
Witaj :)
dane mr=750g, d=1,05g/cm3=1050g/dm3, cm=0,5M, M=53,5g/mol
szukane ms
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cm = n/V.......d=mr/V......V=mr/d........n=ms/M
cm = ms *d//M*mr
ms = cm*M*mr/d = 0,5mol/dm3 *53,5g/mol *750g //1050g/dm3 =========== ms = 19,107g NH4Cl zawierał ten roztwór.

Semper in altum...................................pozdrawiam :)
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