Odpowiedzi

2010-03-30T15:03:32+02:00
Witaj :)
a.
1mol Cl2 = 70,9g Cl2.............................22,4 dm3
.............15g.....................................x
----------------------------------------------------------------
x = 15g*22,4dm3 /70,9g = 4,74 dm3 chloru w warunkach normalnych.

b.
pV = nRT = mRT/M
V = mRT/pM = 15g *83,1hPa*dm3/mol*K *473K //95hPa*70,9g/mol = 87,54 dm3
zajmuje Cl2 w tych warunkach.

Semper in altum.............................pozdrawiam :)