Odpowiedzi

  • Użytkownik Zadane
2010-03-30T17:01:57+02:00
Na2O+H2O----->2 NaOH

m Na2O=6,2g
M Na2O=23*2+16=46+16=62g/mol
M NaOH= 23+16+1=40g/mol

62g/mol Na2O 6,2 g Na2O

2*40 g/mol NaOH x g NaOH


x= 8g NaOH
3 2 3
2010-03-30T17:09:12+02:00
Witaj :)

Na2O..........+..........H2O---------> 2 NaOH
..62g........................................80g
..6,2g........................................x
-----------------------------------------------------
x = 6,2g *80g /62g = 8g NaOH
Otrzyma się 8g NaOH.

Semper in altum..............................pozdrawiam :)
4 3 4