Odpowiedzi

2010-03-30T17:37:20+02:00
D) d = k/k-1 |*(k-1)
dk-d=k
kd-k=d
k(d-1)=d
k=d/(d-1)

e) e= k-1/k+1 |*(k+1)
ek+e=k-1
ke-k=-e-1
k(e-1)=-e-1 |:
k= (-e-1)/(e-1)

f) f= k+1/k + a
f-a= (k+1)/k |*k
kf-ka=k+1
kf-ka-k=1
k(f-a-1)=1
k=1/(f-a-1)

g) g= 2- 1/k
1/k=2-g |*k
1=-2k-kg
k(-2-g)=1
k= -1/(2+g)

h) h= ka²+k
k(a²+1)=h
k=h/(a²+1)

i ) i=a/2 + 2/k
i - ½a=2/k
k(i-½a)=2
k=2/((2i-a)/2)=4/(2i-a)
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