Odpowiedzi

2010-03-30T19:05:07+02:00
P=W/t

t- 1h-> 60'-> 3600sek
W- 72TJ

P=W/t=72×10¹²/3600s=0,02×10¹²W=20×10⁹W=20GW(gigawatów)

tera=10¹²
5 3 5
2010-03-30T19:07:54+02:00
Witaj :)
dane t=1h=3600s, W=72 TJ
szukane P
---------------------------------------
P = W/t = 72*10(12)J/36*10(2)s = 2*10(10)W = 20*10(9)W = 20 GW.
Moc silnika tejrakiety wynosi 20 GW.

Semper in altum..............................pozdrawiam :)
3 3 3