Odpowiedzi

2010-03-30T20:07:24+02:00
D) d(k-1)=k
dk-d=k
dk-k=d
k(d-1)=d
k=d/(d-1)
e)
e(k+1)=k-1
ek+e=k-1
k(e-1)=-e-1
k= (e+1)/(1-e)
f)
f(k+a)=k+1
fk+fa=k+1
k(f-1)=1-fa
k=(1-fa)/(f-1)
g)
g-2=-1/k
2-g=1/k
k=1/(2-g)
h)
h=a²k+k
h=k(a²+1)
k=h/(a²+1)
i)
i-a/2=2/k
(2i-a)/2=2/k
k=4/(2i-a)
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