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2009-11-01T18:25:22+01:00
R(opór) = U/I

R=72/3 = 24

1/R = 1/R1 + 1/R2, gdzie R1=60 i R=24, stąd :
1/24 = 1/60 + 1/R2
1/R2 = 1/24-1/60 = 1/40

=>R2 = 40 [omów]

2009-11-02T00:02:12+01:00
R = U/I

R = 72[V]/3[A] = 24[Ω]
R₁=60[Ω]
R=24[Ω]

1/R = 1/R₁ + 1/R₂
1/R₂ = 1/R - 1/R₁
1/R₂ = (R₁-R) / RR₁
R₂ = RR₁ / R₁-R
R₂ = 40[Ω]
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