Odpowiedzi

2010-03-31T17:33:56+02:00
SIN L=12\13
COS kwadL=1-144\169
TG L=SIN\COS
CTG L=COS\SIN
A WIEC
cos l= 5\13
tg=12\5
ctg=5\12
2010-03-31T17:34:55+02:00
Sinα=12/13

sin²α+cos²α=1
cos²α=1-sin²α
cos²α=1-(12/13)²
cos²α=1-144/169
cos²α=25/169
cosα=5/13

tgα=sinα/cosα
tgα=12/13:5/15=12/5

ctgα=1/tgα=5/12