Odpowiedzi

2010-03-31T19:50:13+02:00
{ 3 = IxI + IyI
{ 3 = 2IxI + y

3=x+y
3=2x+y

y=3-x
3=2x+3-x
0=x
y=3


3=-x-y
3=-2x+y
6=-3x
x=-1

y=3+2x
y=3-2
y=1
2010-03-31T19:51:27+02:00
3= x+ y/ (-1)
3= 2x + y

-3= -x -y
3= 2x+y
___________
x=0
y= 3