Odpowiedzi

Najlepsza Odpowiedź!
2010-03-31T21:19:24+02:00
Witaj :)
1.
dane λ=825 nm, h=6,62*19(-34)Js,
szukane E
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E = h*f.........λ=cT.......T=1/f........λ=c/f.......f=c/λ
E = hc/λ = 6,62*10(-34)Js *3*10(8)m/s //825*10(-9)m = 2,4*10(-19)J =
E = 2,4*10(-19)J //1,6*10(-19)J/eV = 1,5 eV.
Enerrgia tego fotonu wynosi 2,4*10(-19)J lub 1,5 eV.

2.
dane f=100MHz, h=6,62*18(-34)Js, c=3*10(8)m/s,
szukane p
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p = h/λ........λ=c/f
p = hf/c = 6,62*10(-34)Js *10(8)Hz //3*10(8)m/s = 2,21*10(-34)kgm/s
Pęd takiego kwantu wynosi ok. 2,21*10(-34)kgm/s.

Semper in altum.................................pozdrawiam :)