Odpowiedzi

2009-11-01T20:21:42+01:00
X³+x²-9x-9=x²[x+1]-9[x+1]=[x²-9][x+1]=[x+3][x-3][x+1] →x₁=-3 x₂=3 x₃=-1
2009-11-01T20:49:14+01:00
X^3 +x^2 -9x - 9 = 0
x^2 *(x+1) -9*(x+1) = 0
(x^2 - 9)(x+1) = 0
(x + 3)*(x-3)*(x+1) = 0
x1 = -3
x2 =3
x3 =-1
1 5 1
Najlepsza Odpowiedź!
2009-11-01T21:15:17+01:00
X³+x²-9x-9=0
x²(x+1)-9(x+1)=0
(x+1)(x²-9)=0
(x+1)(x-3)(x+3)=0
x=-1 lub x=3 lub x=-3