Odpowiedzi

2010-04-05T12:47:47+02:00
Sinα × cos²α +sin³α= sinα(cos²α+sin²α)=sinα*1=sinα
2 3 2
2010-04-05T12:49:14+02:00
Sinα × cos²α +sin³α=sinα × (1-sin²α) +sin³α=sinα-sin³α+sin³α=sinα
2 3 2