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2009-11-02T13:38:07+01:00
Mamy tu tylko równanie do policzenia
4(X-3)-(X+1)(X-1)=5(X-1)-(X+3)²-2
4x-12-(x²-1)=5x-5-(x²+6x+9)-2
4x-12-x²+1=5x-5-x²-6x-9-2
4x-12+1=5x-5-6x-9-2
4x-5x+6x=-5-9-2+12-1
5x=-5 /:5
x=-1
2009-11-02T13:55:42+01:00
4(X-3)-(X+1)(X-1)=5(X-1)-(X+3)²-2
(4x-12)-(x²-x+x-1)=5x-5)-(x²+6x+9)-2
4x-12-x²+x-x+1=5x-5-x²-6x-9-2
4x-12-x²+1-5x+5+x²+6x+9+2=0
5x+5=0
a=0,b=5,c=5
Δ=b²-4ac=25-0=25
√Δ=5
x1=-b-√Δ/2a=-5-5/2*0=-10/0=0
x2=0