Odpowiedzi

2009-11-02T15:08:28+01:00
A)z-0,5=(2z-3)*(2z+3)-2*(z-3)²
z-0,5=(4z²-9)-2*(z²-6z+9)
z-0,5=4z²-9-2z²+12z-18
z-0,5-4z²+9+2z²-12z+18=0
-2z²-11z-26,5=0
delta=121-[4*(-2)*(-26,5)]=121-212=-91
b)=z²-2z+1-(z²-4z+4)-2z=1-(1-z²)
z²-2z+1-z²+4z-4-2z=1-1+z²
z²-2z+1-z²+4z-4-2z-1+1-z²=0
-z²-3=0
delta=4*(-3)=-12
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