Odpowiedzi

2010-04-06T17:48:12+02:00
Dane:
m=1ol wody= 10kg
t1= 10C
m2= 1 kg stali
t2= 200C
t1= 10C
c1=4200 J/kg*C
c2= 447J/kg*C
tk=?
Q=mcΔt
Qpobrane = Qoddane
Qpobrane= m2c2(tk-t2)
Qoddane= m1c1(t1-tk)
m2c2(tk-t2) = m2c2(t1-tk)
(tk-t2)= (t1-tk)
tk+tk = t1+t2
2tk= t1+t2 / :2
tk=t1+t2/ 2
tk= 10+200/ 2
tk= 210/2
tk=105 C
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