Odpowiedzi

2012-08-18T10:27:48+02:00

Cm=2mol/dm³

ms=20g

M(Na₂CO₃)=2*23g/mol+12g/mol+3*16g/mol=106g/mol

Vr=?

 

n=ms/M

n=20g / 106g/mol

n=0,19mol

 

Cm=n/Vr      /*Vr

n=Cm*Vr       /:Cm

Vr=n/Cm

 

Vr=0,19mol / 2mol/dm³

Vr=0,095dm³=95cm³