Odpowiedzi

2010-04-09T18:34:30+02:00
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CaCO3 x 6H2O

M CaCO3 x 6H2O = 40 + 12 + 3*16 + 6(1*2 + 16) = 40 + 12 + 48 + 108 = 208 u
% Ca = 40/208 * 100% = 19 %
% C = 12/208 * 100% = 6 %
% O = 144/208 * 100% = 69 %
% H = 12/208 * 100% = 6 %
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MgSO4 x 4H2O

M MgSO4 x 4H2O = 24 + 32 + 4*16 + 4(1*2 + 16) = 24 + 32 + 64 + 72 = 192 u
% Mg = 24/192 * 100% = 12 %
% S = 32/192 * 100% = 17 %
% O = 128/192 * 100% = 67 %
% H = 8/192 * 100% = 4 %
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