Odpowiedzi

2010-04-07T20:34:29+02:00
1)Obw.=43,96
2πr=43.96
πr=43,96/2
r=21,98/π
r=21,98/3.14
r=7

P=πr2=3.14x(7x7)=3.14x49=153.86

2)P=550/7cm2
πr2=550/7
r2=550/7 : 22/7
r2=550/7x7/22
r2=550/22
r2=25
r=5

obw.=2πr=2x22/7x5=22/7x10=220/7cm
1 5 1
2010-04-07T20:36:30+02:00
1.
L= 2πr
43,96= 2*3,14r
6,28r=43,96//:6,28
r=7

P=πrkwadrat
P=3,14 * 49
P=153,86

Odp. Pole koła ma 153,86 :)