Odpowiedzi

2010-04-09T06:34:14+02:00
Oblicz objetosc i pole calkowite czworoscianu foremnego o krawedzi 5cm
Pc=4*a²√3/4
Pc=a²√3
Pc=5²√3
Pc=25√3 cm²

V=1/3Pp*H
H²+(2/3h)=a²
h=a√3/2
h=5√3/2

H²+(2/3*5√3/2)=5²
H²+(5√3/3)=5²
H²+(25*3/9)=25
H²+(25/3)=25
H²=25-8 i 1/3
H²=16 i 2/3
H²=50/3
H=√50/3
H=5√2/√3
H=5√6 /3

V=1/3*25√3/4*5√6 /3
V=1/3*125*3*√2 /12
V=125√2 /12 cm³