Odpowiedzi

2010-04-08T16:08:03+02:00
2[4x-(4y+3x)]-4[3x-(2x-3y)]= 2[4x-4y-3x]-4[3x-2x+3y]=
2(x-4y)-4(x+3y)=2x-8y-4x-12y=-2x-20y
2010-04-08T16:42:25+02:00
2[4x-(4y+3x)]-4[3x-(2x-3y)]= 2[4x-4y-3x]-4[3x-2x+3y]=
2(x-4y)-4(x+3y)=2x-8y-4x-12y=-2x-20y


proste to jest:)
2010-04-08T16:45:14+02:00
2 [4x - (4y + 3x)] - 4 [3x - (2x - 3y)] = 2 (x - 4y) - 4 (x + 3y) = 2x - 8y - 4x - 12y = -2x - 20y